This question was previously asked in

DSSSB PGT English Female General Section - 30 June 2021 Shift 2

- 16% of X
- 24% of X
- 12% of X
- 20% of X

Option 1 : 16% of X

**Given:**

40% of X is equal to Y

**Concept:**

Percentage of gain mark = {(Total gain marks)/(Total number of marks)} × 100

**Calculation:**

⇒ Y = (40/100) × X = 2X/5

⇒ Y% of 40 = (Y/100) × 40 = {(2X/5)/100} × 40 = (2X/500) × 40 = (80/500) × X = (16/100) × X = 16% of X

**∴ The required result will be 16% of X.**

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